pass 88 and 125 easy

125-240524-pass/main.py

@@ -0,0 +1,25 @@
+def isPalindrome(s: str) -> bool:
+    tmp = s
+    tmp = tmp.lower()
+    def is_char(ch):
+        if (ch >= 'a' and ch <= 'z') or (ch >= '0' and ch <= '9'):
+            return True
+        return False
+    exp = []
+    for lt in tmp:
+        if is_char(lt):
+            exp.append(lt)
+    length = len(exp)
+    for index, ele in enumerate(exp):
+        if(exp[index] != exp[length - index - 1]):
+            return False
+    return True
+
+s = 'A man, a plan a canal: Panama'
+print(isPalindrome(s))
+s = " "
+print(isPalindrome(s))
+s = "race a car"
+print(isPalindrome(s))
+s = "0P"
+print(isPalindrome(s))

88-231127-pass/main.py

@@ -0,0 +1,42 @@
+def merge(self, nums1: list[int], m: int, nums2: list[int], n: int) -> None:
+        """
+        Do not return anything, modify nums1 in-place instead.
+        """
+        tmp = []
+        for i in range(m):
+            tmp.append(nums1[i])
+        for num in nums2:
+            tmp.append(num)
+        
+        ind1 = 0
+        ind2 = 0
+        rlt = []
+        if(m == 0 or n == 0):
+            rlt += tmp
+        else:
+            for i in range(m + n):
+                if(nums1[ind1]<= nums2[ind2]):
+                    rlt.append(nums1[ind1])
+                    ind1 += 1
+                    if(ind1 == m):
+                        rlt += nums2[ind2:]
+                        print(i, rlt)
+                        break
+                else:
+                    rlt.append(nums2[ind2])
+                    ind2 += 1
+                    if(ind2 == n):
+                        rlt += nums1[ind1:]
+                        print(i, rlt)
+                        break;
+                print(i, rlt)
+        for i in range(len(rlt)):
+            nums1[i] = rlt[i]
+
+nums1 = [2,0]
+m = 1
+nums2 = [1]
+n = 1
+print(merge(0, nums1, m, nums2, n))
+
+