pass 141 easy
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21
141-240525-pass/main.py
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21
141-240525-pass/main.py
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# Definition for singly-linked list.
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class ListNode:
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def __init__(self, x):
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self.val = x
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self.next = None
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# Definition for singly-linked list.
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# class ListNode:
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# def __init__(self, x):
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# self.val = x
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# self.next = None
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class Solution:
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def hasCycle(self, head: Optional[ListNode]) -> bool:
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cnt = 0
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if head == None: return False
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while cnt < 1e4+10:
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if head.next == None:
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return False
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head = head.next
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cnt += 1
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return True
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42
20-240526-pass/main.py
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42
20-240526-pass/main.py
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class Solution:
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def isValid(self, s: str) -> bool:
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def rcg_type(ch) -> int:
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if ch[0] =='(':
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return 1
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if ch[0] ==')':
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return 2
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if ch[0] =='{':
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return 3
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if ch[0] =='}':
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return 4
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if ch[0] =='[':
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return 5
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if ch[0] ==']':
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return 6
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stack = []
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top_idx = -1
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def is_empty():
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return top_idx == -1
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def set_ele(stack: list, idx: int, ele: int):
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if len(stack) <= idx:
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stack.append(ele)
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else:
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stack[idx] = ele
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for ch in s:
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tp = rcg_type(ch)
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if tp % 2 == 1:
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top_idx += 1
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set_ele(stack, top_idx, tp)
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else:
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if is_empty(): return False
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top_ele = stack[top_idx]
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if tp - top_ele != 1: return False
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top_idx -= 1
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if not is_empty(): return False
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return True
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sol = Solution()
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print(sol.isValid("()"))
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print(sol.isValid("(){}[]"))
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print(sol.isValid("(]"))
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print(sol.isValid("[(])"))
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