1038 simple binary tree search problem
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							| @@ -0,0 +1,125 @@ | ||||
| #include<stdcpp.h> | ||||
| using namespace std; | ||||
|  | ||||
| struct TreeNode { | ||||
|     int val; | ||||
|     TreeNode *left; | ||||
|     TreeNode *right; | ||||
|     TreeNode() : val(0), left(nullptr), right(nullptr) {} | ||||
|     TreeNode(int x) : val(x), left(nullptr), right(nullptr) {} | ||||
|     TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {} | ||||
| }; | ||||
|  | ||||
| class Solution { | ||||
| public: | ||||
|     priority_queue<int, vector<int>, greater<int> > vals; | ||||
|     int cnt = 0; | ||||
|     void traverse(TreeNode * node){ | ||||
|         vals.push(node->val); | ||||
|         cnt++; | ||||
|         if(node->left!=nullptr)  traverse(node->left); | ||||
|         if(node->right!=nullptr)  traverse(node->right); | ||||
|     } | ||||
|     TreeNode* bstToGst(TreeNode* root) { | ||||
|         traverse(root); | ||||
|         int val[110]; | ||||
|         int idx[110]; | ||||
|         int pref[110],sum=0; | ||||
|         for(int i = 0 ; i < cnt ; i++){ | ||||
|             val[i] = vals.top(); | ||||
|             vals.pop(); | ||||
|             if(i==0) | ||||
|                 pref[i] = val[i]; | ||||
|             else{ | ||||
|                 pref[i] = pref[i-1] + val[i]; | ||||
|             } | ||||
|         } | ||||
|         sum = pref[cnt-1]; | ||||
|         for(int i = 0 ; i < cnt ; i++){ | ||||
|             idx[val[i]] = sum - pref[i]; | ||||
|         } | ||||
|         stack<TreeNode*> sta; | ||||
|         sta.push(root); | ||||
|         while(sta.empty() == false){ | ||||
|             TreeNode* top_node = sta.top(); | ||||
|             cout<<"top_node is "<<top_node->val<<endl; | ||||
|             sta.pop(); | ||||
|             if(top_node->left!=nullptr) sta.push(top_node->left); | ||||
|             if(top_node->right!=nullptr) sta.push(top_node->right); | ||||
|             top_node->val+=idx[top_node->val]; | ||||
|         } | ||||
|         cnt = 0; | ||||
|         std::priority_queue<int, std::vector<int>, std::greater<int>> empty; | ||||
|         vals.swap(empty); | ||||
|         return root; | ||||
|     } | ||||
| }; | ||||
|  | ||||
| void create(int * val, int cnt, TreeNode *cur,int idx){ | ||||
|     int left_idx = (idx + 1) * 2 - 1; | ||||
|     int right_idx = (idx + 1) * 2 ; | ||||
|     if(left_idx > cnt){ | ||||
|         cur->left = nullptr; | ||||
|         cur->right = nullptr; | ||||
|         return; | ||||
|     } | ||||
|     if(right_idx > cnt){ | ||||
|         cur->right = nullptr; | ||||
|         return; | ||||
|     } | ||||
|     if(val[left_idx] == -1){ | ||||
|         cur -> left = nullptr; | ||||
|     }else{ | ||||
|         TreeNode * left_child = new TreeNode(val[left_idx]); | ||||
|         cur->left = left_child; | ||||
|         create(val,cnt,left_child,left_idx); | ||||
|     } | ||||
|     if(val[right_idx] == -1){ | ||||
|         cur -> right = nullptr; | ||||
|     }else{ | ||||
|         TreeNode * right_child = new TreeNode(val[right_idx]); | ||||
|         cur->right = right_child; | ||||
|         create(val, cnt, right_child, right_idx); | ||||
|     } | ||||
|     return; | ||||
| } | ||||
| void traverse(TreeNode* node){ | ||||
|     cout<<node->val<<' '; | ||||
|     if(node->left != nullptr){ | ||||
|         traverse(node->left); | ||||
|     } | ||||
|     if(node->right != nullptr){ | ||||
|         traverse(node->right); | ||||
|     } | ||||
|     return; | ||||
| } | ||||
| TreeNode* createTree(int * val, int cnt){ | ||||
|     TreeNode * root = new TreeNode(val[0]); | ||||
|     cout<<"create a tree"<<endl; | ||||
|     create(val,cnt,root, 0); | ||||
|     traverse(root); | ||||
|     cout<<"\ndone"<<endl; | ||||
|     // cout<<endl; | ||||
|     return root; | ||||
| } | ||||
| int main(){ | ||||
|     Solution sol; | ||||
|  | ||||
|     //create example 1 | ||||
|     const int ex1_length = 15; | ||||
|     int ex1_data[ex1_length] = {4,1,6,0,2,5,7,-1,-1,-1,3,-1,-1,-1,8}; | ||||
|     TreeNode * ex1 = createTree(ex1_data, ex1_length); | ||||
|     sol.bstToGst(ex1); | ||||
|     traverse(ex1); | ||||
|     cout<<endl; | ||||
|  | ||||
|     const int ex2_length = 3; | ||||
|     int ex2_data[ex2_length] = {0,-1,1}; | ||||
|     TreeNode * ex2 = createTree(ex2_data,ex2_length); | ||||
|     sol.bstToGst(ex2); | ||||
|     traverse(ex2); | ||||
|     cout<<endl; | ||||
|  | ||||
|  | ||||
|     return 0; | ||||
| } | ||||
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